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Solution: 2014 Fall Final - 15

Author: Michiel Smid

Question

A bowl contains 5 blue balls and 4 red balls. We choose 2 balls uniformly at random. Define the events
  • A = "both balls are red",
  • B = "both balls have the same color".
What is the conditional probability $\Pr(A|B)$?
(a)
$\frac{{4 \choose 2}}{{5 \choose 2}{4 \choose 2}}$
(b)
$\frac{{4 \choose 2}}{{9 \choose 2}}$
(c)
$\frac{{5 \choose 2} + {4 \choose 2}}{{4 \choose 2}}$
(d)
$\frac{{4 \choose 2}}{{5 \choose 2} + {4 \choose 2}}$

Solution

  • Let A = Event that both balls are red
    A occurs when we choose 2 of the 4 red balls
    $ |A| = \binom{4}{2} $
  • Let B = Event that both balls have the same color
    B occurs when we choose 2 of the 5 blue balls or 2 of the 4 red balls
    $ |B| = \binom{5}{2} + \binom{4}{2} $
  • Let $A \cap B$ = Event that both balls are red and both balls have the same color
    $ |A \cap B| = \binom{4}{2} $

$ Pr(A|B) = \frac{|A \cap B|}{|B|} $

$ Pr(A|B) = \frac{\binom{4}{2}}{\binom{5}{2} + \binom{4}{2}} $