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Solution: 2015 Fall Final - 14

Author: Michiel Smid

Question

Let $n$ be the number of students who are writing this exam. Each of these students has a uniformly random birthday, which is independent of the birthdays of the other students. We ignore leap years; thus, the year has 365 days. Define the event
  • A = "at least one student's birthday is on December 21".
What is $\Pr(A)$?
(a)
$1 - (1/365)^{n}$
(b)
$1 - (364/365)^{n}$
(c)
$n \cdot (1/365) \cdot (364/365)^{n-1}$
(d)
$365 \cdot n \cdot (364/365)^{n-1}$

Solution

Let B be the event that no student’s birthday is on December 21.

The first student has a birthday on any day except December 21: $ \frac{364}{365} $

The second student has a birthday on any day except December 21: $ \frac{364}{365} $

The $n$th student has a birthday on any day except December 21: $ \frac{364}{365} $

$ Pr(B) = {\left( \frac{364}{365} \right)}^{n} $

$ Pr(A) = 1 - Pr(B) $

$ Pr(A) = 1 - {\left( \frac{364}{365} \right)}^{n} $