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Solution: 2015 Fall Final - 8

Author: Michiel Smid

Question

Consider the following recursive function:
$f(0) = $ $7,$
$f(n) = $ $2 \cdot f(n - 1) + 1\; \ \text{for all}$ $\text{integers}\ n \geq 1.$
Which of the following is true?
(a)
$f(n) = 4n^{2} + 4n + 7$
(b)
$f(n) = 8n + 7$
(c)
None of the above.
(d)
$f(n) = 2^{n+3} - 1$

Solution

Calculate $ f(1) $

$ f(1) = 2 \cdot f(0) + 1 = 2 \cdot 7 + 1 = 15 $

  • $ f(n) = 8n + 7 $
    $ f(1) = 8 \cdot 1 + 7 = 15 $
  • $ f(n) = 4n^{2} + 4n + 7 $
    $ f(1) = 4 \cdot 1^{2} + 4 \cdot 1 + 7 = 15 $
  • $ f(n) = 2^{n+3} - 1$
    $ f(1) = 2^{1+3} - 1 = 15 $
  • None of the above

$ f(n) = 2^{n+3} - 1$ is true.