Back

Solution: 2018 Fall Final - 11

Author: Michiel Smid

Question

You flip a fair coin 5 times; the flips are independent of each other. What is the probability that in these 5 coin flips, the coin comes up heads an odd number of times?
(a)
1/4
(b)
2/3
(c)
1/2
(d)
1/3

Solution

Answer by Observation

Each flip of a fair coin has two equally likely outcomes:

  • $ H $ (Heads)
  • $ T $ (Tails)

When flipping 5 coins:

  • The total number of possible outcomes is: $2^5 = 32$
  • Half of these outcomes will have an odd number of heads, and the other half will have an even number of heads.

Why Are They Evenly Split?

  • For every outcome with an odd number of heads, there is a corresponding outcome with an even number of heads by flipping one coin from heads to tails (or vice versa).
  • This creates a 1-to-1 correspondence between odd and even outcomes.

Thus, the probability of an odd number of heads is: $P(\text{Odd number of heads}) = \frac{1}{2}$