Back

Solution: 2018 Winter Final - 16

Author: Michiel Smid

Question

You flip a fair coin five times; these five flips are independent. Define the events
  • A = "the first three flips result in $HHH$",
  • B = "the number of $T$ in these five flips is at least two".
Which of the following is correct?
(a)
All of the above.
(b)
The events $A$ and $B$ are not independent.
(c)
The events $A$ and $B$ are independent.
(d)
None of the above.

Solution

We’ll take a slow and systematic approach to this question

  • Let S be the set of all possible outcomes
    $ |S| = 2^5 = 32$
  • Let's determine $A$
    the first three flips are fixed: 1
    the last 2 flips can be either heads or tails: $ 2^2 = 4 $
    $ |A| = 1 \cdot 4 = 4 $
    $ Pr(A) = \frac{4}{32} = \frac{1}{8} $
  • Let's determine $B$
    We choose 2 of the 5 positions to be tails: $ \binom{5}{2} $
    We could also choose 3 of the 5 positions to be tails: $ \binom{5}{3} $
    We could also choose 4 of the 5 positions to be tails: $ \binom{5}{4} $
    We could also choose 5 of the 5 positions to be tails: $ \binom{5}{5} $
    $ |B| = \binom{5}{2} + \binom{5}{3} + \binom{5}{4} + \binom{5}{5} $
    $ |B| = 10 + 10 + 5 + 1 $
    $ |B| = 26 $
    $ Pr(B) = \frac{26}{32} = \frac{13}{16} $
  • Let's determine $A \cap B$
    If the first three flips are heads and you want to have at least two tails, then the two tails must be the last 2 flips
    $ |A \cap B| = 1 $
    $ Pr(A \cap B) = \frac{1}{32} $

Now, let’s check whether it’s independent

$ Pr(A \cap B) = Pr(A) \cdot Pr(B) $

$ \frac{1}{32} = \frac{1}{8} \cdot \frac{13}{16} $

$ \frac{1}{32} = \frac{13}{128} $

Since the two sides are not equal, the events are not independent