Let’s determine A
As can be seen, A occurs 4 out of the 36 possible outcomes.
$ \Pr(A) = \frac{4}{36} $
Let’s determine B
The red die is even half the time
$ \Pr(B) = \frac{1}{2} $
Let’s determine $ \Pr(A \cap B) $
$A \cap B = {(2,3), (4,1)}$
$|A \cap B| = 2$
$ \Pr(A \cap B) = \frac{2}{36} $
Profit
Check if A and B are independent.
$ \Pr(A \cap B) = \Pr(A) \cdot \Pr(B) $
$ \frac{2}{36} = \frac{4}{36} \cdot \frac{1}{2} $
$ \frac{2}{36} = \frac{2}{18} \cdot \frac{1}{2} $
$ \frac{2}{36} = \frac{2}{36} $