You are given a fair die and roll it 12 times. Define the event
- A = "there are exactly two 6's in the sequence of 12 rolls".
What is $\Pr(A)$?
(a)
$12^{2} \cdot \left. 5^{10} \middle/ 6^{12} \right.$
(b)
${12 \choose 2} \cdot \left. 5^{10} \middle/ 6^{12} \right.$
(c)
${12 \choose 2} \cdot \left. 5^{12} \middle/ 6^{12} \right.$
(d)
$12^{2} \cdot \left. 5^{12} \middle/ 6^{12} \right.$