A bitstring is called 00-free, if it does not contain two 0's next to each other.
In class, we have seen that for any $m \geq 1$,
the number of 00-free bitstrings of length $m$ is equal to the $(m+2)$-th Fibonacci number
$f_{m+2}$.
What is the number of 00-free bitstrings of length 77 that have 0 at position 59? (The positions are numbered $1,2,\dots,77$.)