Solution: 2014 Winter Midterm - 3

Author: Michiel Smid

Question

Let $S$ be a set of size 37, and let $x$, $y$, and $z$ be three distinct elements of $S$. How many subsets of $S$ are there that contain $x$ and $y$, but do not contain $z$?

(a)

$2^{37} - 2^{35} - 2^{36}$

(b)

$2^{34}$

(c)

$2^{35}$

(d)

$2^{33}$

Solution

Let’s break it down.

Let $A$ be the set of all subsets of $S$ that contain $x$ and $y$
We take for granted that one of the element has a fixed possibility of being $x$: 1
We take for granted that one of the element has a fixed possibility of being $y$: 1
Now that we've guaranteed that $x$ and $y$ are in the subset, we need to calculate all possible add-ons.
For instance, it could $ (x,y) $ or $ (x,y,a) $ or $ (x,y,a,b) $ or $ (x,y,a,b,z) $ and so many others
Looking at it, it's basically asking for $x$, $y$, and any subset of $S$
We can create subsets from the remaining 35 elements.
$|A| = 2^{35}$
Let $B$ be the set of all subsets of $S$ that contain $x$, $y$ AND $z$
We take for granted that one of the element has a fixed possibility of being $x$: 1
We take for granted that one of the element has a fixed possibility of being $y$: 1
We take for granted that one of the element has a fixed possibility of being $z$: 1
Now that we've guaranteed that $x$, $y$, and $z$ are in the subset, we need to calculate all possible add-ons.
For instance, it could $ (x,y,z) $ or $ (x,y,z,a) $ or $ (x,y,z,a,b) $ or $ (x,y,z,a,b,c) $ and so many others
Looking at it, it's basically asking for $x$, $y$, $z$, and any subset of $S$
We can create subsets from the remaining 34 elements.
$|B| = 2^{34}$

Now, it's pretty much just subtraction. We can subtract B from A to get all subsets that contain $x$ and $y$ but not $z$.

Think about it in a different way. A is the set of all subsets that contain $x$ and $y$. B is the set of all subsets that contain $x$, $y$, and $z$.

By subtracting B from A, we get rid of all subsets that contain $x$, $y$ and $z$.

This pretty much just leaves us with the subsets that contain $x$ and $y$ but not $z$.

$ |A| - |B| = 2^{35} - 2^{34} $

$ |A| - |B| = 2^{34} $