Solution: 2015 Winter Midterm - 13

Author: Michiel Smid

Question

Consider the following recursive algorithm $\Fib$, which takes as input an integer $n \geq 0$:

$\mathbf{Algorithm}\ \Fib(n)\mathrm{:}$
$\mathbf{if}\ n = 0\ \mathrm{or}\ n = 1$
$\mathbf{then}\ f = n$
$\mathbf{else}\ f = \Fib(n - 1) + \Fib(n - 2)$
$\mathbf{endif};$
$\mathbf{return}\ f$

When running $\Fib(99)$, how many calls are there to $\Fib(95)$?

(a)

(b)

(c)

(d)

Solution

We can draw a recursive tree to see how many calls there are to $FIB(95)$.

We can see that there are 5 calls to $FIB(95)$.