Let S be all possible strings of length 14: $ |S| = 26^{14} $
Let B be the event that the string contains at no vowels
The first character can be any of the 21 consonants: 21
The second character can be any of the 21 consonants: 21
…
The 14th character can be any of the 21 consonants: 21
$ |B| = 21^{14} $
$ Pr(B) = \frac{21^{14}}{26^{14}} $
$ Pr(A) = 1 - Pr(B) $
$ Pr(A) = 1 - \frac{21^{14}}{26^{14}} $